If the domain of definition of the integral does not include 0, it is still possible for the integral to be integrable. The integrability of the integral depends on the function being integrated and the behavior of the function within its domain. Excluding 0 from the domain does not automatically make the integral non-integrable; it is possible for the integral to be integrable over a restricted domain that does not include 0. **

An integrable function is a function that can be integrated over a given interval to produce a finite result. In other words, the area under the curve of the function is well-defined and does not approach infinity. Mathematically, a function f(x) is integrable on an interval [a, b] if the definite integral of f(x) over [a, b] exists and is finite. This concept is important in calculus and real analysis, as it allows for the calculation of areas, volumes, and other quantities using the techniques of integration. **

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The integral is still integrable if the domain of definition does not include 0. The integrability of a function is determined by its behavior within the domain of integration, not by the presence of a specific value such as 0. Therefore, the integral can still be evaluated as long as the function is continuous and bounded within the given domain. Including 0 in the domain of definition does not automatically make the integral non-integrable; it depends on the behavior of the function at that specific point. **

No, a function does not have to be continuous to be integrable. A function can be integrable as long as it is bounded and has a finite number of discontinuities. For example, the function f(x) = 1/x is not continuous at x = 0, but it is integrable over the interval [1, 2]. The Riemann integral can still be defined for functions with a finite number of discontinuities, allowing them to be integrable. **

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The function is not integrable just because ln(x) is not defined for 0 because the integral of a function over an interval requires the function to be defined and continuous on that interval. Since ln(x) is not defined for x = 0, the function is not continuous at that point, making it not integrable over the interval that includes 0. This discontinuity at x = 0 prevents the function from having a well-defined integral over that interval. **